Aug 23, 2018 The cathode mix is produced by mixing manganese dioxide, carbon black, and small quantity of aqueous magnesium bromide or perchlorate as the electrolyte. The positive terminal is connected to the end of the carbon cup. The negative terminal is connected to the end of anode drum. The entire system is encapsulated in a crimped tin-plated steel.
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If you want to have an enjoyable time learning Chemistry and being motivated to excel in Chemistry, contact me today at 98287357. Hi Sean,I refer to your reply to Jasmine above. If OH- is at the bottom of the electrochemical series and we’re talking about a dilute sodium chloride solution, oxygen gas is produced at the anode as a result of the position of ions in the electrochemical series, but if it is concentrated sodium chloride, then chlorine gas is produced as a result of the concentration factor.That aside, with reference to the electrochemical series for anions, whereby F- is at the top and OH- at the bottom, isn’t the anions at the bottom more reactive hence easier to discharge in comparison to the anions above? So wouldn’t OH- be more reactive than Cl-, hence the preference for OH- to be discharged (assuming dilute solution)?
If something is not reactive, I assume that it the probability of it being discharged (transformed to something else) is smaller compared to one that is more reactive.I am getting contradicting information that the anions further up the series are more reactive than the ones at the bottom. I agree that F is reactive, that’s why it becomes F- which is more stable, so to say that F- is reactive is not accurate is it?Look forward to your reply.Thank you!.Lin says. Hi, would like to ask the products formed at both cathode and anode for (i) lead nitrate solution and (ii) Nickel sulfate solution?For lead nitrate solution,Is it true that cathode: lead metal is formed instead of hydrogen gas being produced?
I thought according to the position of metals in reactivity series, lead ions is above ‘hydrogen’?As for nickel sulfate solution,Is it true as well that cathode: nickel metal is formed instead of hydrogen gas being produced? I thought according to the position of metals in reactivity series, nickel ions is above ‘hydrogen’ as well?.sean says. Sorry but i do not know how to edit my previous post.
But i got a question to add on.my question is that if there is an electrolysis reaction with inert electrode and the electrolyte is concentrated aqueous potassium nitrate, what would be the ions that will be discharged at the cathode and the anode?my focus is on the anode, since it is concentrated, by right the nitrate ion will be discharged, but i see the information above, you put that nitrate ion (Do Not Discharge), meaning even if the electrolyte is concentrated, hydroxide ion would be discharged instead?please clear my doubts and thanks a lot!.TKS says. Hi Miranda,Yes! Of course i do cos it is covered under the chapter: Qualitative Analysis or commonly also known as Chemical Analysis.Both Lead and Aluminum ions are Cations (+ve ions).We can differentiate them using Sodium Hydroxide or Aqueous Ammonia.Do you know the colour/state change when we add either Sodium Hydroxide or Aqueous Ammonia to Lead or Aluminum ions???PS: Hear from you.PPS: Anyone out there would like to contribute to this question?Cheers,Sean ChuaMaster Trainer @ SimpleChemConcepts.comAuthor of Up Your Chemistry Grades Now! Book.Miranda says. Hi Jasmine,You are spot on!In the blogpost, i have share with you that the products of electrolysis are determined by:1.
Position of metal in the reactivity series2. Concentration of the ion in the electrolyte3. Nature of the electrode usedConcentration of Ions is an important factor to consider when it comes to predicting the products of electrolysis.In this case, although Cl- is more reactive to be discharged at the +ve cathode, OH- ions is present in higher concentration (since DILUTE SOLUTIONS) & will be selectively discharged at the platinum inert cathode.Hope this helps in getting your Chemistry Concepts on the right track before your major chemistry exams.All The Best to Your Academic Success in Chemistry,SeanMaster Trainer.Jasmine says. Hi Jasmine,Good try.Part (i) is correct. For aqueous salt solutions, there are H+ and OH- bsides the Na+ and Cl- ions.For Part (ii), do note that @ Anode, Oxygen gas is produced.This is because OH- ions are preferentially discharged over Cl- ions.Hope this helps.PS: I am launching the ebook?Up Your Chemistry Grades Nows!? Before it is being published into hardcopy.
There is a major section that have a comprehensive discussion of major / common mistakes made by students.To your Academic Success in Chemistry,Sean ChuaMaster Trainer.Jasmine says.
Part A: What substance is produced at the cathode during the electrolysis of molten calcium bromide, CaBr2? Assume standard conditions.Express your answer as a chemical formula.Part B: What substance is produced at the anode during the electrolysis of molten calcium bromide, CaBr2? Assume standard conditions.Part C: What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, CaBr2(l), and molten magnesium iodide MgI2(l),? Assume standard conditions.Express your answer as a chemical formula.Part D: What substance is produced at the anode during the electrolysis of a mixture of molten calcium bromide,CaBr2(l), and molten magnesium iodideMgI2(l),?
Assume standard conditions. Expert Answer 100% (22 ratings).